3.1025 \(\int \frac {1}{x^5 \sqrt [3]{1-x^2} (3+x^2)^2} \, dx\)

Optimal. Leaf size=208 \[ -\frac {\left (1-x^2\right )^{2/3}}{36 x^2 \left (x^2+3\right )}+\frac {\left (1-x^2\right )^{2/3}}{216 \left (x^2+3\right )}+\frac {13 \log \left (x^2+3\right )}{1296\ 2^{2/3}}+\frac {1}{36} \log \left (1-\sqrt [3]{1-x^2}\right )-\frac {13 \log \left (2^{2/3}-\sqrt [3]{1-x^2}\right )}{432\ 2^{2/3}}-\frac {13 \tan ^{-1}\left (\frac {\sqrt [3]{2-2 x^2}+1}{\sqrt {3}}\right )}{216\ 2^{2/3} \sqrt {3}}+\frac {\tan ^{-1}\left (\frac {2 \sqrt [3]{1-x^2}+1}{\sqrt {3}}\right )}{18 \sqrt {3}}-\frac {\left (1-x^2\right )^{2/3}}{12 x^4 \left (x^2+3\right )}-\frac {\log (x)}{54} \]

[Out]

1/216*(-x^2+1)^(2/3)/(x^2+3)-1/12*(-x^2+1)^(2/3)/x^4/(x^2+3)-1/36*(-x^2+1)^(2/3)/x^2/(x^2+3)-1/54*ln(x)+13/259
2*ln(x^2+3)*2^(1/3)+1/36*ln(1-(-x^2+1)^(1/3))-13/864*ln(2^(2/3)-(-x^2+1)^(1/3))*2^(1/3)-13/1296*arctan(1/3*(1+
(-2*x^2+2)^(1/3))*3^(1/2))*3^(1/2)*2^(1/3)+1/54*arctan(1/3*(1+2*(-x^2+1)^(1/3))*3^(1/2))*3^(1/2)

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Rubi [A]  time = 0.15, antiderivative size = 208, normalized size of antiderivative = 1.00, number of steps used = 13, number of rules used = 9, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.409, Rules used = {446, 103, 151, 156, 55, 618, 204, 31, 617} \[ -\frac {\left (1-x^2\right )^{2/3}}{36 x^2 \left (x^2+3\right )}-\frac {\left (1-x^2\right )^{2/3}}{12 x^4 \left (x^2+3\right )}+\frac {\left (1-x^2\right )^{2/3}}{216 \left (x^2+3\right )}+\frac {13 \log \left (x^2+3\right )}{1296\ 2^{2/3}}+\frac {1}{36} \log \left (1-\sqrt [3]{1-x^2}\right )-\frac {13 \log \left (2^{2/3}-\sqrt [3]{1-x^2}\right )}{432\ 2^{2/3}}-\frac {13 \tan ^{-1}\left (\frac {\sqrt [3]{2-2 x^2}+1}{\sqrt {3}}\right )}{216\ 2^{2/3} \sqrt {3}}+\frac {\tan ^{-1}\left (\frac {2 \sqrt [3]{1-x^2}+1}{\sqrt {3}}\right )}{18 \sqrt {3}}-\frac {\log (x)}{54} \]

Antiderivative was successfully verified.

[In]

Int[1/(x^5*(1 - x^2)^(1/3)*(3 + x^2)^2),x]

[Out]

(1 - x^2)^(2/3)/(216*(3 + x^2)) - (1 - x^2)^(2/3)/(12*x^4*(3 + x^2)) - (1 - x^2)^(2/3)/(36*x^2*(3 + x^2)) - (1
3*ArcTan[(1 + (2 - 2*x^2)^(1/3))/Sqrt[3]])/(216*2^(2/3)*Sqrt[3]) + ArcTan[(1 + 2*(1 - x^2)^(1/3))/Sqrt[3]]/(18
*Sqrt[3]) - Log[x]/54 + (13*Log[3 + x^2])/(1296*2^(2/3)) + Log[1 - (1 - x^2)^(1/3)]/36 - (13*Log[2^(2/3) - (1
- x^2)^(1/3)])/(432*2^(2/3))

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 55

Int[1/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(1/3)), x_Symbol] :> With[{q = Rt[(b*c - a*d)/b, 3]}, -Simp[L
og[RemoveContent[a + b*x, x]]/(2*b*q), x] + (Dist[3/(2*b), Subst[Int[1/(q^2 + q*x + x^2), x], x, (c + d*x)^(1/
3)], x] - Dist[3/(2*b*q), Subst[Int[1/(q - x), x], x, (c + d*x)^(1/3)], x])] /; FreeQ[{a, b, c, d}, x] && PosQ
[(b*c - a*d)/b]

Rule 103

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(b*(a +
b*x)^(m + 1)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/((m + 1)*(b*c - a*d)*(b*e - a*f)), x] + Dist[1/((m + 1)*(b*
c - a*d)*(b*e - a*f)), Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p*Simp[a*d*f*(m + 1) - b*(d*e*(m + n + 2) +
c*f*(m + p + 2)) - b*d*f*(m + n + p + 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && LtQ[m, -1] &&
IntegerQ[m] && (IntegerQ[n] || IntegersQ[2*n, 2*p])

Rule 151

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[((b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/((m + 1)*(b*c - a*d)*(b*e - a*
f)), x] + Dist[1/((m + 1)*(b*c - a*d)*(b*e - a*f)), Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p*Simp[(a*d*f*
g - b*(d*e + c*f)*g + b*c*e*h)*(m + 1) - (b*g - a*h)*(d*e*(n + 1) + c*f*(p + 1)) - d*f*(b*g - a*h)*(m + n + p
+ 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && LtQ[m, -1] && IntegerQ[m]

Rule 156

Int[(((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)))/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))), x_Symbol] :>
Dist[(b*g - a*h)/(b*c - a*d), Int[(e + f*x)^p/(a + b*x), x], x] - Dist[(d*g - c*h)/(b*c - a*d), Int[(e + f*x)
^p/(c + d*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, h}, x]

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 446

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.), x_Symbol] :> Dist[1/n, Subst[Int
[x^(Simplify[(m + 1)/n] - 1)*(a + b*x)^p*(c + d*x)^q, x], x, x^n], x] /; FreeQ[{a, b, c, d, m, n, p, q}, x] &&
NeQ[b*c - a*d, 0] && IntegerQ[Simplify[(m + 1)/n]]

Rule 617

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[(a*c)/b^2]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + (2*c*x)/b], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 618

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Dist[-2, Subst[Int[1/Simp[b^2 - 4*a*c - x^2, x], x]
, x, b + 2*c*x], x] /; FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rubi steps

\begin {align*} \int \frac {1}{x^5 \sqrt [3]{1-x^2} \left (3+x^2\right )^2} \, dx &=\frac {1}{2} \operatorname {Subst}\left (\int \frac {1}{\sqrt [3]{1-x} x^3 (3+x)^2} \, dx,x,x^2\right )\\ &=-\frac {\left (1-x^2\right )^{2/3}}{12 x^4 \left (3+x^2\right )}-\frac {1}{12} \operatorname {Subst}\left (\int \frac {-1-\frac {7 x}{3}}{\sqrt [3]{1-x} x^2 (3+x)^2} \, dx,x,x^2\right )\\ &=-\frac {\left (1-x^2\right )^{2/3}}{12 x^4 \left (3+x^2\right )}-\frac {\left (1-x^2\right )^{2/3}}{36 x^2 \left (3+x^2\right )}+\frac {1}{36} \operatorname {Subst}\left (\int \frac {6+\frac {4 x}{3}}{\sqrt [3]{1-x} x (3+x)^2} \, dx,x,x^2\right )\\ &=\frac {\left (1-x^2\right )^{2/3}}{216 \left (3+x^2\right )}-\frac {\left (1-x^2\right )^{2/3}}{12 x^4 \left (3+x^2\right )}-\frac {\left (1-x^2\right )^{2/3}}{36 x^2 \left (3+x^2\right )}+\frac {1}{432} \operatorname {Subst}\left (\int \frac {24-\frac {2 x}{3}}{\sqrt [3]{1-x} x (3+x)} \, dx,x,x^2\right )\\ &=\frac {\left (1-x^2\right )^{2/3}}{216 \left (3+x^2\right )}-\frac {\left (1-x^2\right )^{2/3}}{12 x^4 \left (3+x^2\right )}-\frac {\left (1-x^2\right )^{2/3}}{36 x^2 \left (3+x^2\right )}+\frac {1}{54} \operatorname {Subst}\left (\int \frac {1}{\sqrt [3]{1-x} x} \, dx,x,x^2\right )-\frac {13}{648} \operatorname {Subst}\left (\int \frac {1}{\sqrt [3]{1-x} (3+x)} \, dx,x,x^2\right )\\ &=\frac {\left (1-x^2\right )^{2/3}}{216 \left (3+x^2\right )}-\frac {\left (1-x^2\right )^{2/3}}{12 x^4 \left (3+x^2\right )}-\frac {\left (1-x^2\right )^{2/3}}{36 x^2 \left (3+x^2\right )}-\frac {\log (x)}{54}+\frac {13 \log \left (3+x^2\right )}{1296\ 2^{2/3}}-\frac {1}{36} \operatorname {Subst}\left (\int \frac {1}{1-x} \, dx,x,\sqrt [3]{1-x^2}\right )+\frac {1}{36} \operatorname {Subst}\left (\int \frac {1}{1+x+x^2} \, dx,x,\sqrt [3]{1-x^2}\right )-\frac {13}{432} \operatorname {Subst}\left (\int \frac {1}{2 \sqrt [3]{2}+2^{2/3} x+x^2} \, dx,x,\sqrt [3]{1-x^2}\right )+\frac {13 \operatorname {Subst}\left (\int \frac {1}{2^{2/3}-x} \, dx,x,\sqrt [3]{1-x^2}\right )}{432\ 2^{2/3}}\\ &=\frac {\left (1-x^2\right )^{2/3}}{216 \left (3+x^2\right )}-\frac {\left (1-x^2\right )^{2/3}}{12 x^4 \left (3+x^2\right )}-\frac {\left (1-x^2\right )^{2/3}}{36 x^2 \left (3+x^2\right )}-\frac {\log (x)}{54}+\frac {13 \log \left (3+x^2\right )}{1296\ 2^{2/3}}+\frac {1}{36} \log \left (1-\sqrt [3]{1-x^2}\right )-\frac {13 \log \left (2^{2/3}-\sqrt [3]{1-x^2}\right )}{432\ 2^{2/3}}-\frac {1}{18} \operatorname {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1+2 \sqrt [3]{1-x^2}\right )+\frac {13 \operatorname {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1+\sqrt [3]{2-2 x^2}\right )}{216\ 2^{2/3}}\\ &=\frac {\left (1-x^2\right )^{2/3}}{216 \left (3+x^2\right )}-\frac {\left (1-x^2\right )^{2/3}}{12 x^4 \left (3+x^2\right )}-\frac {\left (1-x^2\right )^{2/3}}{36 x^2 \left (3+x^2\right )}-\frac {13 \tan ^{-1}\left (\frac {1+\sqrt [3]{2-2 x^2}}{\sqrt {3}}\right )}{216\ 2^{2/3} \sqrt {3}}+\frac {\tan ^{-1}\left (\frac {1+2 \sqrt [3]{1-x^2}}{\sqrt {3}}\right )}{18 \sqrt {3}}-\frac {\log (x)}{54}+\frac {13 \log \left (3+x^2\right )}{1296\ 2^{2/3}}+\frac {1}{36} \log \left (1-\sqrt [3]{1-x^2}\right )-\frac {13 \log \left (2^{2/3}-\sqrt [3]{1-x^2}\right )}{432\ 2^{2/3}}\\ \end {align*}

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Mathematica [A]  time = 0.18, size = 194, normalized size = 0.93 \[ \frac {-\frac {72 \left (1-x^2\right )^{2/3}}{x^2 \left (x^2+3\right )}+\frac {12 \left (1-x^2\right )^{2/3}}{x^2+3}+13 \sqrt [3]{2} \log \left (x^2+3\right )+72 \log \left (1-\sqrt [3]{1-x^2}\right )-39 \sqrt [3]{2} \log \left (2^{2/3}-\sqrt [3]{1-x^2}\right )-26 \sqrt [3]{2} \sqrt {3} \tan ^{-1}\left (\frac {\sqrt [3]{2-2 x^2}+1}{\sqrt {3}}\right )+48 \sqrt {3} \tan ^{-1}\left (\frac {2 \sqrt [3]{1-x^2}+1}{\sqrt {3}}\right )-\frac {216 \left (1-x^2\right )^{2/3}}{x^4 \left (x^2+3\right )}-48 \log (x)}{2592} \]

Antiderivative was successfully verified.

[In]

Integrate[1/(x^5*(1 - x^2)^(1/3)*(3 + x^2)^2),x]

[Out]

((12*(1 - x^2)^(2/3))/(3 + x^2) - (216*(1 - x^2)^(2/3))/(x^4*(3 + x^2)) - (72*(1 - x^2)^(2/3))/(x^2*(3 + x^2))
- 26*2^(1/3)*Sqrt[3]*ArcTan[(1 + (2 - 2*x^2)^(1/3))/Sqrt[3]] + 48*Sqrt[3]*ArcTan[(1 + 2*(1 - x^2)^(1/3))/Sqrt
[3]] - 48*Log[x] + 13*2^(1/3)*Log[3 + x^2] + 72*Log[1 - (1 - x^2)^(1/3)] - 39*2^(1/3)*Log[2^(2/3) - (1 - x^2)^
(1/3)])/2592

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fricas [A]  time = 0.86, size = 265, normalized size = 1.27 \[ -\frac {52 \cdot 4^{\frac {1}{6}} \sqrt {3} \left (-1\right )^{\frac {1}{3}} {\left (x^{6} + 3 \, x^{4}\right )} \arctan \left (\frac {1}{6} \cdot 4^{\frac {1}{6}} {\left (2 \, \sqrt {3} \left (-1\right )^{\frac {1}{3}} {\left (-x^{2} + 1\right )}^{\frac {1}{3}} - 4^{\frac {1}{3}} \sqrt {3}\right )}\right ) + 13 \cdot 4^{\frac {2}{3}} \left (-1\right )^{\frac {1}{3}} {\left (x^{6} + 3 \, x^{4}\right )} \log \left (4^{\frac {1}{3}} \left (-1\right )^{\frac {2}{3}} {\left (-x^{2} + 1\right )}^{\frac {1}{3}} - 4^{\frac {2}{3}} \left (-1\right )^{\frac {1}{3}} + {\left (-x^{2} + 1\right )}^{\frac {2}{3}}\right ) - 26 \cdot 4^{\frac {2}{3}} \left (-1\right )^{\frac {1}{3}} {\left (x^{6} + 3 \, x^{4}\right )} \log \left (-4^{\frac {1}{3}} \left (-1\right )^{\frac {2}{3}} + {\left (-x^{2} + 1\right )}^{\frac {1}{3}}\right ) - 96 \, \sqrt {3} {\left (x^{6} + 3 \, x^{4}\right )} \arctan \left (\frac {2}{3} \, \sqrt {3} {\left (-x^{2} + 1\right )}^{\frac {1}{3}} + \frac {1}{3} \, \sqrt {3}\right ) + 48 \, {\left (x^{6} + 3 \, x^{4}\right )} \log \left ({\left (-x^{2} + 1\right )}^{\frac {2}{3}} + {\left (-x^{2} + 1\right )}^{\frac {1}{3}} + 1\right ) - 96 \, {\left (x^{6} + 3 \, x^{4}\right )} \log \left ({\left (-x^{2} + 1\right )}^{\frac {1}{3}} - 1\right ) - 24 \, {\left (x^{4} - 6 \, x^{2} - 18\right )} {\left (-x^{2} + 1\right )}^{\frac {2}{3}}}{5184 \, {\left (x^{6} + 3 \, x^{4}\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^5/(-x^2+1)^(1/3)/(x^2+3)^2,x, algorithm="fricas")

[Out]

-1/5184*(52*4^(1/6)*sqrt(3)*(-1)^(1/3)*(x^6 + 3*x^4)*arctan(1/6*4^(1/6)*(2*sqrt(3)*(-1)^(1/3)*(-x^2 + 1)^(1/3)
- 4^(1/3)*sqrt(3))) + 13*4^(2/3)*(-1)^(1/3)*(x^6 + 3*x^4)*log(4^(1/3)*(-1)^(2/3)*(-x^2 + 1)^(1/3) - 4^(2/3)*(
-1)^(1/3) + (-x^2 + 1)^(2/3)) - 26*4^(2/3)*(-1)^(1/3)*(x^6 + 3*x^4)*log(-4^(1/3)*(-1)^(2/3) + (-x^2 + 1)^(1/3)
) - 96*sqrt(3)*(x^6 + 3*x^4)*arctan(2/3*sqrt(3)*(-x^2 + 1)^(1/3) + 1/3*sqrt(3)) + 48*(x^6 + 3*x^4)*log((-x^2 +
1)^(2/3) + (-x^2 + 1)^(1/3) + 1) - 96*(x^6 + 3*x^4)*log((-x^2 + 1)^(1/3) - 1) - 24*(x^4 - 6*x^2 - 18)*(-x^2 +
1)^(2/3))/(x^6 + 3*x^4)

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giac [A]  time = 0.45, size = 181, normalized size = 0.87 \[ -\frac {13}{2592} \cdot 4^{\frac {2}{3}} \sqrt {3} \arctan \left (\frac {1}{12} \cdot 4^{\frac {2}{3}} \sqrt {3} {\left (4^{\frac {1}{3}} + 2 \, {\left (-x^{2} + 1\right )}^{\frac {1}{3}}\right )}\right ) + \frac {13}{5184} \cdot 4^{\frac {2}{3}} \log \left (4^{\frac {2}{3}} + 4^{\frac {1}{3}} {\left (-x^{2} + 1\right )}^{\frac {1}{3}} + {\left (-x^{2} + 1\right )}^{\frac {2}{3}}\right ) - \frac {13}{2592} \cdot 4^{\frac {2}{3}} \log \left (4^{\frac {1}{3}} - {\left (-x^{2} + 1\right )}^{\frac {1}{3}}\right ) + \frac {1}{54} \, \sqrt {3} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, {\left (-x^{2} + 1\right )}^{\frac {1}{3}} + 1\right )}\right ) + \frac {{\left (-x^{2} + 1\right )}^{\frac {2}{3}}}{216 \, {\left (x^{2} + 3\right )}} - \frac {{\left (-x^{2} + 1\right )}^{\frac {2}{3}}}{36 \, x^{4}} - \frac {1}{108} \, \log \left ({\left (-x^{2} + 1\right )}^{\frac {2}{3}} + {\left (-x^{2} + 1\right )}^{\frac {1}{3}} + 1\right ) + \frac {1}{54} \, \log \left (-{\left (-x^{2} + 1\right )}^{\frac {1}{3}} + 1\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^5/(-x^2+1)^(1/3)/(x^2+3)^2,x, algorithm="giac")

[Out]

-13/2592*4^(2/3)*sqrt(3)*arctan(1/12*4^(2/3)*sqrt(3)*(4^(1/3) + 2*(-x^2 + 1)^(1/3))) + 13/5184*4^(2/3)*log(4^(
2/3) + 4^(1/3)*(-x^2 + 1)^(1/3) + (-x^2 + 1)^(2/3)) - 13/2592*4^(2/3)*log(4^(1/3) - (-x^2 + 1)^(1/3)) + 1/54*s
qrt(3)*arctan(1/3*sqrt(3)*(2*(-x^2 + 1)^(1/3) + 1)) + 1/216*(-x^2 + 1)^(2/3)/(x^2 + 3) - 1/36*(-x^2 + 1)^(2/3)
/x^4 - 1/108*log((-x^2 + 1)^(2/3) + (-x^2 + 1)^(1/3) + 1) + 1/54*log(-(-x^2 + 1)^(1/3) + 1)

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maple [F]  time = 1.69, size = 0, normalized size = 0.00 \[ \int \frac {1}{\left (-x^{2}+1\right )^{\frac {1}{3}} \left (x^{2}+3\right )^{2} x^{5}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x^5/(-x^2+1)^(1/3)/(x^2+3)^2,x)

[Out]

int(1/x^5/(-x^2+1)^(1/3)/(x^2+3)^2,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (x^{2} + 3\right )}^{2} {\left (-x^{2} + 1\right )}^{\frac {1}{3}} x^{5}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^5/(-x^2+1)^(1/3)/(x^2+3)^2,x, algorithm="maxima")

[Out]

integrate(1/((x^2 + 3)^2*(-x^2 + 1)^(1/3)*x^5), x)

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mupad [B]  time = 1.01, size = 416, normalized size = 2.00 \[ \frac {\ln \left (\frac {9109}{10077696}-\frac {9109\,{\left (1-x^2\right )}^{1/3}}{10077696}\right )}{54}-\frac {13\,2^{1/3}\,\ln \left (-\frac {169\,2^{2/3}\,\left (\frac {13\,2^{1/3}\,\left (\frac {2535\,2^{2/3}}{64}-\frac {7419\,{\left (1-x^2\right )}^{1/3}}{64}\right )}{1296}-\frac {469}{3456}\right )}{1679616}-\frac {845\,{\left (1-x^2\right )}^{1/3}}{5038848}\right )}{1296}+\frac {\frac {{\left (1-x^2\right )}^{5/3}}{54}-\frac {23\,{\left (1-x^2\right )}^{2/3}}{216}+\frac {{\left (1-x^2\right )}^{8/3}}{216}}{6\,{\left (x^2-1\right )}^2+{\left (x^2-1\right )}^3+9\,x^2-5}+\ln \left ({\left (-\frac {1}{108}+\frac {\sqrt {3}\,1{}\mathrm {i}}{108}\right )}^2\,\left (\left (-\frac {1}{108}+\frac {\sqrt {3}\,1{}\mathrm {i}}{108}\right )\,\left (393660\,{\left (-\frac {1}{108}+\frac {\sqrt {3}\,1{}\mathrm {i}}{108}\right )}^2-\frac {7419\,{\left (1-x^2\right )}^{1/3}}{64}\right )+\frac {469}{3456}\right )-\frac {845\,{\left (1-x^2\right )}^{1/3}}{5038848}\right )\,\left (-\frac {1}{108}+\frac {\sqrt {3}\,1{}\mathrm {i}}{108}\right )-\ln \left (-{\left (\frac {1}{108}+\frac {\sqrt {3}\,1{}\mathrm {i}}{108}\right )}^2\,\left (\left (\frac {1}{108}+\frac {\sqrt {3}\,1{}\mathrm {i}}{108}\right )\,\left (393660\,{\left (\frac {1}{108}+\frac {\sqrt {3}\,1{}\mathrm {i}}{108}\right )}^2-\frac {7419\,{\left (1-x^2\right )}^{1/3}}{64}\right )-\frac {469}{3456}\right )-\frac {845\,{\left (1-x^2\right )}^{1/3}}{5038848}\right )\,\left (\frac {1}{108}+\frac {\sqrt {3}\,1{}\mathrm {i}}{108}\right )+\frac {13\,{\left (-1\right )}^{1/3}\,2^{1/3}\,\ln \left (\frac {169\,{\left (-1\right )}^{2/3}\,2^{2/3}\,\left (\frac {13\,{\left (-1\right )}^{1/3}\,2^{1/3}\,\left (\frac {2535\,{\left (-1\right )}^{2/3}\,2^{2/3}}{64}-\frac {7419\,{\left (1-x^2\right )}^{1/3}}{64}\right )}{1296}+\frac {469}{3456}\right )}{1679616}-\frac {845\,{\left (1-x^2\right )}^{1/3}}{5038848}\right )}{1296}-\frac {13\,{\left (-1\right )}^{1/3}\,2^{1/3}\,\ln \left (-\frac {845\,{\left (1-x^2\right )}^{1/3}}{5038848}+\frac {169\,{\left (-1\right )}^{2/3}\,2^{2/3}\,{\left (1+\sqrt {3}\,1{}\mathrm {i}\right )}^2\,\left (\frac {13\,{\left (-1\right )}^{1/3}\,2^{1/3}\,\left (1+\sqrt {3}\,1{}\mathrm {i}\right )\,\left (\frac {7419\,{\left (1-x^2\right )}^{1/3}}{64}-\frac {2535\,{\left (-1\right )}^{2/3}\,2^{2/3}\,{\left (1+\sqrt {3}\,1{}\mathrm {i}\right )}^2}{256}\right )}{2592}+\frac {469}{3456}\right )}{6718464}\right )\,\left (1+\sqrt {3}\,1{}\mathrm {i}\right )}{2592} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^5*(1 - x^2)^(1/3)*(x^2 + 3)^2),x)

[Out]

log(9109/10077696 - (9109*(1 - x^2)^(1/3))/10077696)/54 - (13*2^(1/3)*log(- (169*2^(2/3)*((13*2^(1/3)*((2535*2
^(2/3))/64 - (7419*(1 - x^2)^(1/3))/64))/1296 - 469/3456))/1679616 - (845*(1 - x^2)^(1/3))/5038848))/1296 + ((
1 - x^2)^(5/3)/54 - (23*(1 - x^2)^(2/3))/216 + (1 - x^2)^(8/3)/216)/(6*(x^2 - 1)^2 + (x^2 - 1)^3 + 9*x^2 - 5)
+ log(((3^(1/2)*1i)/108 - 1/108)^2*(((3^(1/2)*1i)/108 - 1/108)*(393660*((3^(1/2)*1i)/108 - 1/108)^2 - (7419*(1
- x^2)^(1/3))/64) + 469/3456) - (845*(1 - x^2)^(1/3))/5038848)*((3^(1/2)*1i)/108 - 1/108) - log(- ((3^(1/2)*1
i)/108 + 1/108)^2*(((3^(1/2)*1i)/108 + 1/108)*(393660*((3^(1/2)*1i)/108 + 1/108)^2 - (7419*(1 - x^2)^(1/3))/64
) - 469/3456) - (845*(1 - x^2)^(1/3))/5038848)*((3^(1/2)*1i)/108 + 1/108) + (13*(-1)^(1/3)*2^(1/3)*log((169*(-
1)^(2/3)*2^(2/3)*((13*(-1)^(1/3)*2^(1/3)*((2535*(-1)^(2/3)*2^(2/3))/64 - (7419*(1 - x^2)^(1/3))/64))/1296 + 46
9/3456))/1679616 - (845*(1 - x^2)^(1/3))/5038848))/1296 - (13*(-1)^(1/3)*2^(1/3)*log((169*(-1)^(2/3)*2^(2/3)*(
3^(1/2)*1i + 1)^2*((13*(-1)^(1/3)*2^(1/3)*(3^(1/2)*1i + 1)*((7419*(1 - x^2)^(1/3))/64 - (2535*(-1)^(2/3)*2^(2/
3)*(3^(1/2)*1i + 1)^2)/256))/2592 + 469/3456))/6718464 - (845*(1 - x^2)^(1/3))/5038848)*(3^(1/2)*1i + 1))/2592

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{x^{5} \sqrt [3]{- \left (x - 1\right ) \left (x + 1\right )} \left (x^{2} + 3\right )^{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x**5/(-x**2+1)**(1/3)/(x**2+3)**2,x)

[Out]

Integral(1/(x**5*(-(x - 1)*(x + 1))**(1/3)*(x**2 + 3)**2), x)

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